Official solution
Let A = {0, 1, 2, 3, 4, ......., 10}
Total number of ways of selecting 2 different numbers from A is
n (S) = 11C2 = 55, where 'S' denotes sample space
Let E be the given event
\[ \therefore \] E = {(0, 4), (0, 8), (2, 6), (2, 10), (4, 8), (6, 10)}
\[ \Rightarrow \] n (E) = 6
\[ \therefore \] P(E) = \[{{n\left( E \right)} \over {n\left( S \right)}}\] = \[{6 \over {55}}\]