Official solution
Given that,
\[P\left( {{A \over B}} \right) = {1 \over 2}\]
\[ \Rightarrow \] \[{{P\left( {A \cap B} \right)} \over {P\left( B \right)}}\] = \[{1 \over 2}\].............. equation (1)
\[P\left( {{B \over A}} \right) = {2 \over 3}\]
\[ \Rightarrow \] \[{{P\left( {A \cap B} \right)} \over {P\left( A \right)}}\] = \[{2 \over 3}\].............. equation (2)
Dividing equation (1) by equation (2) we get,
\[{{P\left( A \right)} \over {P\left( B \right)}}\] = \[{3 \over 4}\]
\[ \Rightarrow \] \[{P\left( B \right)}\] = \[{4 \over 3}\] \[ \times \] \[{P\left( A \right)}\]
= \[{4 \over 3}\] \[ \times \] \[{1 \over 4}\]
= \[{1 \over 3}\]
\[\therefore\] Option (B) is correct.