One die has two faces marked 1 , two faces marked 2 , one face marked 3 and one face marke…

Question

One die has two faces marked 1 , two faces marked 2 , one face marked 3 and one face marked 4 . Another die has one face marked 1 , two faces marked 2 , two faces marked 3 and one face marked 4. The probability of getting the sum of numbers...

Accepted Answer

$a=$ number or dice 1

$b=$ number on dice 2

$(a,b)=(1,3),(3,1),(2,2),(2,3),(3,2),(1,4),(4,1)$

Required probability

$\begin{gathered} =\frac{2}{6}	imes \frac{2}{6}+\frac{1}{6}	imes \frac{1}{6}+\frac{2}{6}	imes \frac{2}{6}+\frac{2}{6}	imes \frac{2}{6}+\frac{1}{6}	imes \frac{2}{6}+\frac{2}{6}	imes \frac{1}{6}+\frac{1}{6}	imes \frac{2}{6} \ =\frac{18}{36}=\frac{1}{2} \end{gathered}$

Solutions · 1