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Joint Entrance Examination
Mathematics
Probability
Question 279
Question 279 of 417
Medium
MCQ
X
X
X
has Poisson distribution with mean 2. Find
P
(
X
>
1.5
)
P(X>1.5)
P
(
X
>
1.5
)
.
A
2
/
e
2
2/e^2
2/
e
2
B
0
C
1
−
3
/
e
2
1-3/e^2
1
−
3/
e
2
D
3
/
e
2
3/e^2
3/
e
2
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Official solution
P
(
X
>
1.5
)
=
P
(
X
≥
2
)
=
1
−
P
(
0
)
−
P
(
1
)
=
1
−
e
−
2
−
2
e
−
2
=
1
−
3
e
2
P(X>1.5) = P(X\ge2) = 1-P(0)-P(1) = 1-e^{-2}-2e^{-2} = 1-\dfrac{3}{e^2}
P
(
X
>
1.5
)
=
P
(
X
≥
2
)
=
1
−
P
(
0
)
−
P
(
1
)
=
1
−
e
−
2
−
2
e
−
2
=
1
−
e
2
3
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