A number x chosen from 1,,100.

Question

A number $x$ chosen from $\{1,\dots,100\}$. Event $A$: $\dfrac{(x-10)(x-50)}{x-30}\ge0$. Find $P(A)$.

Accepted Answer

The inequality holds for $x\in[10,30)\cup[50,100]$: giving $20+51=71$ values.

$$P(A) = \frac{71}{100}=0.71$$

Solutions · 1