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Joint Entrance Examination
Mathematics
Probability
Question 218
Question 218 of 417
Medium
MCQ
Two cards drawn successively with replacement from 52 cards.
X
X
X
=number of aces. Find
P
(
X
=
1
)
+
P
(
X
=
2
)
P(X=1)+P(X=2)
P
(
X
=
1
)
+
P
(
X
=
2
)
.
A
49
/
169
49/169
49/169
B
52
/
169
52/169
52/169
C
24
/
169
24/169
24/169
D
25
/
169
25/169
25/169
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Official solution
\[P(X=1) = 2\times\frac{4}{52}\times\frac{48}{52}=\frac{24}{169},\qquad P(X=2)=\left(\frac{4}{52}\right)^2=\frac{1}{169}\] \[P(X=1)+P(X=2) = \frac{25}{169}\]
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