Four dice thrown, numbers recorded in a 2×2 matrix. Find the probability the matrix has all different entries and is non-singular.
Solutions · 1
Official solution
n(S)=64. Counting singular matrices (ad=bc) with all distinct entries gives 16 cases (via cross-ratio analysis over {1,…,6}). Number with all-distinct entries: 6C4×4!=360.
\[P = \frac{360-16}{1296} = \frac{344}{1296}\]
*(The source's final simplified value is 43/162.)*