Find the probability that two randomly selected subsets of {1,2,3,4,5} have exactly two elements in their intersection.
Solutions · 1
Official solution
Choose the 2 common elements: 5C2 ways. Each of the remaining 3 elements can independently be in A only, B only, or neither: 33 ways.
\[P = \frac{{}^5C_2\times3^3}{2^5\times2^5} = \frac{10\times27}{2^{10}}=\frac{135}{2^9}\]