The probability that a randomly selected 3-digit number has at least two odd digits, is

Question

Accepted Answer

Exactly 3 odd digits: $5^3=125$. Exactly 2 odd digits: with 0 used, $2\times5\times5=50$; without 0, ${}^3C_1\times4\times5\times5=300$.

$$P = \frac{125+50+300}{900} = \frac{475}{900}=\frac{19}{36}$$

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