Question 140 of 417MediumMCQ
Let a die be rolled n times. If P(odd 7 times)=P(odd 9 times), and P(even twice)=215k, find k. Solutions · 1
Official solution
nC7=nC9⇒n=16.
\[P(\text{even twice}) = {}^{16}C_2\left(\frac12\right)^{16} = \frac{120}{2^{16}}=\frac{60}{2^{15}} \implies k=60\] Answer the question to unlock