Let N denote the number that turns up when a fair die is rolled. If the probability that the system of equations x+y+z=1, 2x+Ny+2z=2, 3x+3y+Nz=3 has a unique solution is 6k, then the sum of k and all possible values of N is
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Official solution
For unique solution Δ=0
i.e. 1231N312N=0⇒(N2−6)−(2N−6)+(6−3N)=0⇒N2−5N+6=0∴N=2 and N=3∴ Probability of not getting 2 or 3 in a throw of dice =32
As given 32=6k⇒k=4∴ Required value =1+4+5+6+4=20