Two distinct numbers a and b are selected at random from 1,2,3,…,50. The probability, that their product ab is divisible by 3 , is
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Official solution
Total ways to choose two distinct numbers from 1,2,…,50 is
(250)=1225.
The product ab is not divisible by 3 only if neither a nor b is divisible by 3.
Multiples of 3 in 1 to 50: ⌊350⌋=16.
So numbers not divisible by 3: 50−16=34.
Unfavorable pairs:
(234)=234⋅33=561.
Therefore favorable pairs:
1225−561=664,
and the required probability is
1225664.
Answer: 1225664 (Option C).