The set S={1,2,3,…,12} is to be partitioned into three sets A, B, C of equal size. Thus A∪B∪C=S, A∩B=B∩C=A∩C=∅. The number of ways to partition S is:
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Official solution
Each set has 4 elements. Choose A: (412), then B from remaining 8: (48), then C is fixed: (44).
\[\binom{12}{4}\binom84\binom44 = \frac{12!}{4!8!}\cdot\frac{8!}{4!4!}\cdot\frac{4!}{4!0!} = \frac{12!}{(4!)^3}\]