If the number of 5-element subsets of the set A={a1,…,a20} of 20 distinct elements is k times the number of 5-element subsets containing a4, then k is:
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Official solution
Total 5-element subsets: (520). Subsets containing a4: (419) (choose remaining 4 from the other 19).
\[\binom{20}{5} = k\cdot\binom{19}{4} \implies \frac{20!}{5!15!} = k\cdot\frac{19!}{4!15!} \implies \frac{20}{5}=k \implies k=4\]