Question 216 of 278MediumMCQ
The number of integers greater than 6,000 that can be formed using the digits 3, 5, 6, 7 and 8, without repetition, is:
Solutions · 1
Official solution
4-digit numbers greater than 6000: first digit from {6,7,8} (3 choices), remaining 3 digits arranged from remaining 4: 4×3×2=24: total 3×24=72.
5-digit numbers (all automatically >6000): 5!=120.
\[\text{Total} = 72+120 = 192\] Answer the question to unlock