The number of ways, in which the letters A, B, C, D, E can be placed in the 8 boxes of the figure below so that no row remains empty and at most one letter can be placed in a box, is :
Solutions · 1
Official solution
Let x,y,z be the number of box which are filled
⇒1≤x≤3,1≤y≤3,1≤z≤2xyz
Number of ways
3
1
1
3C3⋅3C1⋅2C1=6
2
2
1
3C2⋅3C2⋅2C1=18
1
3
1
3C1⋅3C3⋅2C1=6
2
1
2
3C2⋅3C1⋅2C2=9
1
2
2
3C1⋅3C2⋅2C2=9
Total ways =(48) to fill boxes
Now to arrange a,b,c,d and e
Number of ways will be 48.5! = 5760