The sum of all three-digit numbers less than or equal to 500, that are formed without using the digit 1 and they all are multiples of 11, is:
Answer: 7744
Solutions · 1
Official solution
3-digit multiples of 11, less than 500: 121,132,…,495, count =11495−121+1=35, sum =235(121+495)=10780.
Now subtract those containing digit 1 (which must be excluded).
Multiples of 11 (< 500) with 1 in the hundreds place: 121 to 198, count 8, sum =28(121+198)=1276.
With 1 in the tens place (hundreds =1): 319,418, sum =737.
With 1 in the units place (hundreds, tens =1): 231,341,451, sum =1023.
\[\text{Required sum} = 10780 - 1276 - 737 - 1023 = 7744\]