If the sides AB, BC and CA of a triangle △ABC have 3, 5 and 6 interior points respectively, then the total number of triangles that can be constructed using these points as vertices, is equal to:
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Official solution
Total number of triangles
= \[{}^{14}{C_3} - {}^3{C_3} - {}^5{C_3} - {}^6{C_3}\]
= 364 -- 31 = 333