If the chord joining the points P1(t1) and P2(t2) on the parabola y2=12x subtends a right angle at the vertex of the parabola, then x1x2−y1y2 is equal to \_\_\_\_\_\_\_\_.
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Official solution
Here a=3. A chord subtending a right angle at the vertex of y2=4ax satisfies t1t2=−4.
\[x_1x_2=a^2(t_1t_2)^2=9\times16=144,\qquad y_1y_2=4a^2t_1t_2=4\times9\times(-4)=-144.\]
x1x2−y1y2=144−(−144)=288.