Official solution
Let the equation of the normal is
y = mx - 2am - am3
here 4a = 2 \[ \Rightarrow \] a = \[{1 \over 2}\]
y = mx - m - \[{1 \over 2}\]m3
It passing through A(a, 0) then
0 = am - m - \[{1 \over 2}\]m3
m = 0, a - 1 - \[{1 \over 2}\]m2 = 0
m2 = 2(a - 1) > 0
\[ \Rightarrow \] a > 1