Official solution
\[y = mx + {1 \over m}\] (tangent at y2
= 4x)
y = mx -- m2
(tangent at x2
= 4y)
\[{1 \over m} = - {m^2}\] (for common tangent)
m3
= -- 1
\[ \Rightarrow \] m = - 1
\[ \therefore \] Equation of tangent
y = --x --1
x + y + 1 = 0
This line touches circle whose center at (0, 0),
\[ \therefore \] apply p( Distance from center of the circle of the line ) = r ( Radius of the circle )
c = \[\left| {{{0 + 0 + 1} \over {\sqrt 2 }}} \right| = {1 \over {\sqrt 2 }}\]