Official solution
x2 = 8y
\[ \Rightarrow \] \[{{dy} \over {dx}} = {x \over 4} = \tan \theta \]
\[ \therefore \] x1 = 4tan\[\theta \]
y1 = 2 tan2 \[\theta \]
Equation of tangent :-
y - 2tan2\[\theta \] = tan\[\theta \] (x - 4tan \[\theta \])
\[ \Rightarrow \] x = y cot \[\theta \] + 2 tan \[\theta \]