Tangents drawn from the point (−8,0) to the parabola y2=8x touch the parabola at P and Q. If F is the focus of the parabola, then the area of the triangle PFQ (in sq. units) is equal to
Solutions · 1
Official solution
a=2; chord of contact from (−8,0): y(0)=4(x−8)⇒x=8. Then y2=64⇒y=±8: P=(8,8),Q=(8,−8).
Focus F=(2,0); base PQ=16, height =∣8−2∣=6:
\[\text{Area}=\frac12(16)(6)=48.\]