\[\text { Let } A=\left[\[1000αβ0βα\]\right] \text { and }|2 \mathrm{~A}|\^3=2\^{21} \text { where } \alpha, \beta \in Z \text {, Then a value of } \alpha \text { is }\]
Solutions · 1
Official solution
\[∣A∣=α2−β2∣2A∣3=221⇒∣A∣=24α2−β2=16(α+β)(α−β)=16⇒α=4 or 5\]