Question 44 of 472MediumMCQ
For some a,b, let f(x)=a+xsinx1ba1+xsinxba1b+xsinx,x=0,x→0limf(x)=λ+μa+νb. Then (λ+μ+v)2 is equal to : Solutions · 1
Official solution
x→0limf(x)=∣a+11ba1+1ba1b+1∣=(a+1)(2(b+1)−b)+1(ab−a(b+1))+ba=(a+1)(b+2)−a+ab=b+a+2=λ+μa+vbλ=2,μ=1,v=1⇒(λ+μ+v)2=16 Answer the question to unlock