Question 430 of 472MediumMCQ
Let \[\alpha\] and \[\beta\] be real numbers. Consider a 3 \[\times\] 3 matrix A such that \[A^2=3A+\alpha I\]. If \[A^4=21A+\beta I\], then
Solutions · 1
Official solution
A2=3 A+αI
A3=3A2+αA
A3=3(3 A+αI)+αA
A3=9 A+αA+3αI
A4=(9+α)A2+3αA
=(9+α)(3 A+αI)+3αA
=A(27+6α)+α(9+α)
⇒27+6α=21⇒α=−1
⇒β=α(9+α)=−8 Answer the question to unlock