Let \[A=\left(\[\begin{gathered} 4 \quad -2 \\ \alpha \quad \beta \end{gathered}\]\right)\].
If \[\mathrm{A}^{2}+\gamma \mathrm{A}+18 \mathrm{I}=\mathrm{O}\], then \[\operatorname{det}(\mathrm{A})\] is equal to \_\_\_\_\_\_\_\_\_\_\_\_\_.
Solutions · 1
Official solution
Characteristic equation of A is given by
\[\left| {A - \lambda I} \right| = 0\]
\[\left| {(4−λα−2β−λ) } \right| = 0\]
\[ \Rightarrow {\lambda ^2} - (4 + \beta )\lambda + (4\beta + 2\alpha ) = 0\]
So, \[{A^2} - (4 + \beta )A + (4\beta + 2\alpha )I = 0\]
\[|A| = 4\beta + 2\alpha = 18\]