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Joint Entrance Examination
Mathematics
Matrices and Determinants
Question 354
Question 354 of 472
Medium
MCQ
If A = \[\left[ {
(
1
sin
θ
1
−
sin
θ
1
sin
θ
−
1
−
sin
θ
1
)
\begin{pmatrix} 1 & {\sin \theta } & 1 \\ { - \sin \theta } & 1 & {\sin \theta } \\ { - 1} & { - \sin \theta } & 1 \\ \end{pmatrix}
1
−
sin
θ
−
1
sin
θ
1
−
sin
θ
1
sin
θ
1
} \right]\]; then for all \[\theta \] \[ \in \] \[\left( {{{3\pi } \over 4},{{5\pi } \over 4}} \right)\], det (A) lies in the interval :
A
\[\left( {{3 \over 2},3} \right]\]
B
\[\left( {0,{3 \over 2}} \right]\]
C
\[\left[ {{5 \over 2},4} \right)\]
D
\[\left( {1,{5 \over 2}} \right]\]
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Official solution
\[\left| A \right| = \left| {
(
1
sin
θ
1
−
sin
θ
1
sin
θ
−
1
−
sin
θ
1
)
\begin{pmatrix} 1 & {\sin \theta } & 1 \\ { - \sin \theta } & 1 & {\sin \theta } \\ { - 1} & { - \sin \theta } & 1 \\ \end{pmatrix}
1
−
sin
θ
−
1
sin
θ
1
−
sin
θ
1
sin
θ
1
} \right|\] = 2(1 + sin2\[\theta \]) \[\theta \] \[ \in \] \[\left( {{{3\pi } \over 4},{{5\pi } \over 4}} \right) \Rightarrow {1 \over {\sqrt 2 }} < \sin \theta < {1 \over {\sqrt 2 }}\] \[ \Rightarrow \] 0 \[ \le \] sin2\[\theta \] < \[{1 \over 2}\] \[ \therefore \] \[\left| A \right| \in \left[ {2,3} \right)\]
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