Question 301 of 472MediumMCQ
The matrix A2+4A−5I, where I is the identity matrix and A=(142−3), equals: Solutions · 1
Official solution
A2=(9−8−417).
\[A^2+4A-5I=(9−8−417)+(4168−12)-(5005)=(8840)=4(2210).\] Answer the question to unlock