Let A=111 and B=92122−152−102132162112−142172. Then the value of ATBA is:
Solutions · 1
Official solution
ATBA=(111)B111 is the sum of all entries of B:
\[\big(9^2-10^2+11^2\big)+\big(12^2+13^2-14^2\big)+\big(-15^2+16^2+17^2\big).\]
\[=(81-100+121)+(144+169-196)+(-225+256+289)=102+117+320=539.\]