Let A be a 3×3 real matrix such that A110=111, A101=−101, and A001=112. If X=(x1,x2,x3)T and I is the identity matrix of order 3, then the system (A−2I)X=411 has:
Solutions · 1
Official solution
From the given images, the columns of A can be reconstructed: the third column is 112; using A110=col1+col2=111 and A101=col1+col3=−101, one solves for columns 1 and 2.
Checking det(A−2I), one finds it is singular (zero determinant), and the given RHS vector 411 is consistent with the row space (i.e. the augmented matrix has the same rank as the coefficient matrix), so the system has infinitely many solutions.