Let A be a 3×3 matrix such that ∣adj(adj(adjA))∣=124. Then ∣A−1adjA∣ is equal to
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Official solution
For a 3×3 matrix, ∣adj(adj(adjA))∣=∣A∣(3−1)3=∣A∣8.
So ∣A∣8=124=(22⋅3)4=28⋅34, giving ∣A∣=2⋅31/2=23 (taking the positive real root, since 28⋅34=(23)8).
∣A−1adjA∣=∣A−1∣⋅∣adjA∣=∣A∣1⋅∣A∣3−1=∣A∣=23.