Let A be a 3×3 matrix of non-negative real elements such that A[[∣111]]∣=3[[∣111]]∣. Then the maximum value of det(A) is \_\_\_\_\_\_\_\_\_.
Answer: 27
Solutions · 1
Official solution
Let A=[[∣a11a12a13a21a22a23a31a32a33]]∣
Now
A[[∣111]]∣=3[[∣111]]∣[[∣a11a12a13a21a22a23a31a32a33]]∣[[∣111]]∣=[[∣333]]∣a11+a12+a13=3a21+a22+a23=3a31+a32+a33=3
Now for maximum value of det(A)=aij0i=j3i=j∴∣A∣=27