The system of equations
−kx+3y−14z=25−15x+4y−kz=3−4x+y+3z=4
is consistent for all k in the set
Solutions · 1
Official solution
The system may be inconsistent if
\[\left| {−k−15−4341−14−k3 } \right| = 0 \Rightarrow k = \, \pm \,11\]
Hence if system is consistent then \[k \in R - \{ 11, - 11\} \].