Official solution
\[ * ,\, \odot \in \{ \wedge ,\, \vee \} \]
Now for \[(p * q) \odot (p \odot \sim q)\] is tautology
(A) \[( \vee , \wedge ):(p \vee q) \wedge (p \wedge \sim q)\] not a tautology
(B) \[( \vee , \vee ):(p \vee q) \vee (p \vee \sim q)\]
\[ = P \vee T\] is tautology
(C) \[( \wedge , \wedge ):(p \wedge q) \wedge (p \wedge \sim q)\]
\[ = (p \wedge p) \wedge (q \wedge \sim q) = p \wedge F\] not a tautology (Fallasy)
(D) \[( \wedge , \vee ):(p \wedge q) \vee (p \vee \sim q)\] not a tautology