Official solution
LHS of all the options are same i.e.
\[((P \to Q) \wedge \sim Q)\]
\[ \equiv ( \sim P \vee Q) \wedge \sim Q\]
\[ \equiv ( \sim P \wedge \sim Q) \vee (Q \wedge \sim Q)\]
\[ \equiv \sim P \wedge \sim Q\]
(A) \[( \sim P \wedge \sim Q) \to Q\]
\[ \equiv \sim ( \sim P \wedge \sim Q) \vee Q\]
\[ \equiv (P \vee Q) \vee Q \ne \] Tautology
(B) \[( \sim P \wedge \sim Q) \to P\]
\[ \equiv \sim ( \sim P \wedge \sim Q) \vee \sim P\]
\[ \equiv (P \vee Q) \vee \sim P\]
(C) \[( \sim P \wedge \sim Q) \to P\]
\[ \equiv (P \wedge Q) \wedge P \ne \] Tautology
(D) \[( \sim P \wedge \sim Q) \to (P \vee Q)\]
\[ \equiv (P \wedge Q) \wedge (P \vee Q) \ne \] Tautology