If (p \[ \wedge \] \[ \sim \] q) \[ \wedge \] (p \[ \wedge \] r) \[ \to \] \[ \sim \] p \[ \vee \] q is false, then the truth values of p,q and r are, respectively :
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Official solution
From the truth table you can see (p \[ \wedge \] ~q) \[ \wedge \] (p \[ \wedge \] r) \[\to\] ~p \[\vee\] q is false only when values of (p, q, r) is (T, F, T).