The negation of [(p ( q)) ( p)] is equivalent to :

Question

The negation of $$(p \wedge(\sim q)) \vee(\sim p)$$ is equivalent to :

Accepted Answer

$$
\begin{aligned}
& (p \wedge(\sim q)) \vee(\sim p) \\
& \equiv(p \vee \sim p) \wedge(\sim q \vee \sim p) \\
& \equiv \mathrm{T} \wedge(\sim q \vee \sim p) \\
& \equiv \sim q \vee \sim p \text { negation } p \wedge q
\end{aligned}
$$

Solutions · 1