Choose the correct statement about two circles whose equations are given below.
\[x^2+y^2-10x-10y+41=0,\qquad x^2+y^2-22x-10y+137=0\]
Solutions · 1
Official solution
Circle 1: centre (5,5), r12=25+25−41=9⇒r1=3. Circle 2: centre (11,5), r22=121+25−137=9⇒r2=3.
Distance between centres =6=r1+r2 --- the circles touch externally, so they have exactly one meeting point.