Exams Joint Entrance Examination Mathematics Limits, Continuity and Differentiability Question 73 Question 73 of 401 Medium NUMERICAL
The value of l i m x → 0 2 ( 1 − cos x cos 2 x 3 cos 3 x … x 2 ) \underset{x\to 0}{lim}2(\frac{1-\cos x\sqrt{\cos 2x}\sqrt{3}\cos 3x}{\ldots }{x}^{2}) x → 0 l im 2 ( … 1 − c o s x c o s 2 x 3 c o s 3 x x 2 ) is \_\_\_\_\_\_\_\_\_\_.
Answer: 55
Solutions · 1 Post your solution Official solution
l i m x → 0 2 ( 1 − cos x ( cos 2 x ) 1 2 ( cos 3 x ) 1 3 . . . ( cos 10 x ) 1 10 x 2 ) \underset{x\to 0}{lim}2(\frac{1-\cos x{(\cos 2x)}^{\frac{1}{2}}{(\cos 3x)}^{\frac{1}{3}}\, ...\, {(\cos 10x)}^{\frac{1}{10}}}{{x}^{2}}) x → 0 l im 2 ( x 2 1 − c o s x ( c o s 2 x ) 2 1 ( c o s 3 x ) 3 1 ... ( c o s 10 x ) 10 1 ) ( 0 0 ) (\frac{0}{0}) ( 0 0 )
Using L' hospital
2 l i m x → 0 sin x ( cos 2 x ) 1 2 … ( cos 10 x ) 1 10 … ( sin 2 x ) ( cos x ) ( cos 3 x ) 1 3 + … 2 x 2\underset{x\to 0}{lim}\frac{\sin x(\cos 2x{)}^{\frac{1}{2}}\ldots (\cos 10x{)}^{\frac{1}{10}}\ldots (\sin 2x)(\cos x)(\cos 3x{)}^{\frac{1}{3}}+\ldots }{2x} 2 x → 0 l im 2 x s i n x ( c o s 2 x ) 2 1 … ( c o s 10 x ) 10 1 … ( s i n 2 x ) ( c o s x ) ( c o s 3 x ) 3 1 + …
⇒ l i m x → 0 ( sin x x + sin 2 x x + … + sin 10 x x ) = 1 + 2 + … + 10 = 55 \begin{gathered} \Rightarrow \underset{x\to 0}{lim}(\frac{\sin x}{x}+\frac{\sin 2x}{x}+\ldots +\frac{\sin 10x}{x}) \\ \, =1+2+\ldots +10=55 \end{gathered} ⇒ x → 0 l im ( x sin x + x sin 2 x + … + x sin 10 x ) = 1 + 2 + … + 10 = 55 Answer the question to unlock