Consider the function f:(0,2) R defined by f(x)=(x)/(2)+(2)/(x) and the function g(x) defi…

Question

Consider the function $f:(0,2)	o R$ defined by $f(x)=\frac{x}{2}+\frac{2}{x}$ and the function $g(x)$ defined by

$g(x)= \begin{array}{|c|c|} min\lfloor f(t), & 0<t\le x0<x\le 1 \ \frac{3}{2}+x, & 1<x<2 \end{array}.$

Accepted Answer

$\begin{gathered} f:(0,2)	o R;f(x)=\frac{x}{2}+\frac{2}{x} \ {f}^{'}(x)=\frac{1}{2}-\frac{2}{{x}^{2}} \end{gathered}$

$	herefore f(x)$

Solutions · 1