Let ,f:[−1,2]→R be given by f(x)=2x2+x+[x2]−[x], where [t] denotes the greatest integer less than or equal to t. The number of points, where f is not continuous, is :
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Official solution
\[f(x)=2x2+x+[x2]−[x]=2x2+[x2]+{x}f(−1)=2+1+0=3f(−1+)=2+0+0=2f(0−)=0+1=1f(0+)=0+0+0=0f(1+)=2+1+0=3\]
\[f(1−)=2+0+1=3f(2−)=8+3+1=12f(2+)=8+4+0=12\]
\[\therefore\] discontinuous at \[x=0, \sqrt{2}, \sqrt{3},-1\]