Official solution
Here \[\mathop {\lim }\limits_{x \to 0} \left| {{{1 - x + \left| x \right|} \over {\lambda - x + [x]}}} \right| = L\]
Here L.H.L. \[\mathop {\lim }\limits_{h \to 0^-} \left| {{{1 + h + h} \over {\lambda + h - 1}}} \right| = \left| {{1 \over {\lambda - 1}}} \right|\]
R.H.L. = \[\mathop {\lim }\limits_{h \to 0^+} \left| {{{1 - h + h} \over {\lambda + h + 0}}} \right| = \left| {{1 \over \lambda }} \right|\]
\[ \because \] Limit exists. Hence L.H.L. = R.H.L.
\[ \Rightarrow \] \[\left| {\lambda - 1} \right| = \left| \lambda \right|\]
\[ \Rightarrow \] \[\lambda = {1 \over 2}\]
\[ \therefore \] L = \[{1 \over {\left| \lambda \right|}}\] = 2