Question 31 of 401MediumMCQ
If the function
f(x)=x2sin(k1+1)x+sin(k2−1)x,x0
is continuous at x=0, then k21+k22 is equal to : Solutions · 1
Official solution
x→0−limx2sin(k1+1)x+sin(k2−1)x=4⇒2(k1+1)+2(k2−1)=4⇒k1+k2=2⇒x→0+limx2ln(2+k2x2+k1x)=4⇒x→0+limx1ln(1+2+k2x(k1−k2)x)=2⇒2k1−k2=2⇒k1−k2=4∴k1=3,k2=−1k21+k22=9+1=10 Answer the question to unlock