Exams Joint Entrance Examination Mathematics Limits, Continuity and Differentiability Question 307 Question 307 of 401 Medium MCQ
For each t \[ \in R\], let [t] be the greatest integer less than or equal to t.
Then \[\mathop {\lim }\limits_{x \to {0^ + }} x\left( {\left[ {{1 \over x}} \right] + \left[ {{2 \over x}} \right] + ..... + \left[ {{{15} \over x}} \right]} \right)\]
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Given,
\[\mathop {lim}\limits_{x \to {0^ + }} \,\,x\,\left( {\left[ {{1 \over x}} \right] + \left[ {{2 \over x}} \right]} \right. + \] \[\left. {\,.\,.\,.\,.\,.\, + \left[ {{{15} \over x}} \right]} \right)\]
as we know that
\[{1 \over x} = \left[ {{1 \over x}} \right] + \left\{ {{1 \over x}} \right\}\]
\[ \Rightarrow \,\,\,\,\left[ {{1 \over x}} \right] = {1 \over x} - \left\{ {{1 \over x}} \right\}\]
\[ = \,\,\,\,\mathop {\lim }\limits_{x \to {0^ + }} \,\,x\left[ {{1 \over x} - \left\{ {{1 \over x}} \right\} + {2 \over 2} - \left\{ {{2 \over x}} \right\} + ........{{15} \over x} - \left\{ {{{15} \over x}} \right\}} \right]\]
\[ = \,\,\,\,\mathop {\lim }\limits_{x \to {0^ + }} \,\left[ {x.{1 \over x} + x.{2 \over x} + .....x.{{15} \over x}} \right]\]
\[\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, - \,\left[ {x.\left\{ {{1 \over 2}} \right\} + .. + x.\left\{ {{{15} \over x}} \right\}} \right]\]
We know \[\left\{ {{1 \over x}} \right\}\] is fractional part of \[{1 \over x}.\]
So, the range of \[\,\left\{ {{1 \over x}} \right\}\] is \[0 \le \left\{ {{1 \over x}} \right\} < 1\]
So, \[\mathop {lim}\limits_{x \to {0^ + }} \,\,x\,\left\{ {{1 \over x}} \right\} = 0.\] (finite no) = 0 =0 = 0
Similarly \[\mathop {\lim }\limits_{x \to {0^ + }} x.\left\{ {{2 \over x}} \right\} = 0\]
\[ = \,\,\,\,\left( {1 + 2 + ... + 15} \right) - \left( {0 + 0...} \right)\]
\[ = \,\,\,\,{{15 \times 16} \over 2}\]
\[ = \,\,\,\,120\] Answer the question to unlock