Question 29 of 401MediumMCQ
Let f:R−0→R be a function such that f(x)−6f(x1)=3x35−25. If the x→0lim(αx1+f(x))=β;α,β∈R, then α+2β is equal to Solutions · 1
Official solution
F(x)−6f(1/x)=3x35−25
=x→0lim(αx1−2x−3x1+21)α=3,B=1/2α+2B=3+1=4 Answer the question to unlock