Question 22 of 401MediumMCQ
Let f(x)=(1+ax)1/x,x0 be continuous at x=0. Then eabc is equal to: Solutions · 1
Official solution
f(x)=(1+ax)1/x,x0
f(0)=1+6RHL=x→0+lim(x+c)1/3−2(x+4)1/2−2[00c=8]
=x→0lim(1+8x)1/3−22(1+4x)1/2−2=x→0lim1+8x⋅31−11+8x−1=81⋅3181=3∴1+b=3⇒b=2
LHL=x→0lim(1+ax)1/x=x→0limex1+ax−1=ea=3∴ea⋅bc=3⋅2.8=48 Answer the question to unlock