Let f:(-1,1)R be a function defined by f(x)=-|x|,-√1-x^2.

Question

Let $f:(-1,1)	o\mathbb{R}$ be a function defined by $f(x)=\max\left\{-|x|,-\sqrt{1-x^2}ight\}$. If $K$ is the set of all points at which $f$ is not differentiable, then $K$ has exactly:

Accepted Answer

f : (- 1, 1) $$ \to $$ R

f(x) = max {- $$\left| x \right|, - \sqrt {1 - {x^2}} $$}

Non-derivable at 3 points in (-1, 1)

Solutions · 1