Let [t] denote the greatest integer ≤t and x→0limx[x4]=A. Then the function f(x)=[x2]sin(πx) is discontinuous, when x is equal to:
Solutions · 1
Official solution
x→0limx[x4]=x→0lim(4−x{x4})=4, so A=4.
f(x)=[x2]sinπx is discontinuous wherever x2 is a non-negative integer but x is not an integer (so that sinπx=0 at the jump). x=A+1=5, which is not an integer, so f is discontinuous there.