Question 8 of 155MediumMCQ
The value of cot−1(tan(2)1+tan2(2)−1)−cot−1(tan(21)1+tan2(21)+1) is equal to Solutions · 1
Official solution
cot−1(tan2∣sec2∣−1)−cot−1(tan21∣sec21∣+1)
\[=cot−1(sin2−1−cos2)−cot−1(sin211+cos21)=π−cot−1(cot1)−cot−1(cot41)=π−1−41=π−45\] Answer the question to unlock